]> git.leopard-lacewing.eu Git - zahlenTA.git/commitdiff
UE2 (Vorlage)
authorPeter Schaefer <schaeferpm@gmail.com>
Tue, 17 Apr 2012 19:57:57 +0000 (21:57 +0200)
committerPeter Schaefer <schaeferpm@gmail.com>
Tue, 17 Apr 2012 19:57:57 +0000 (21:57 +0200)
Vorlesung.pdf
Vorlesung.tex
ue2.pdf [new file with mode: 0644]
ue2.tex [new file with mode: 0644]

index 6d8444f3c39612de788b0fea73ff46489f27ba33..5670b99bb68f6fec49274f02b44305914ed30b99 100644 (file)
Binary files a/Vorlesung.pdf and b/Vorlesung.pdf differ
index d2a0c4eaa2dd7c694992191289e371af4034b763..8cc6ce8ffbcd0f45d0a9c635f28110a8b972b4ac 100644 (file)
@@ -22,7 +22,7 @@
 
 \begin{document}
 \maketitle
-\section{Vorlesung}
+\section*{Vorlesung 21.3.12}
 \subsection*{Bew. 1.16}
 
 \begin{enumerate}
@@ -77,8 +77,11 @@ Analytisch fortzetzen:
 \zeta(s) & =   \frac{\eta(s)}{(1-2^{1-s})}
 \end{align}
 
-Riemann-Siegel-Formel?
 
+
+\section*{Vorlesung 28.3.12}
+
+Riemann-Siegel-Formel?
 \begin{align}
  L_x(s) &s= \sum_{n=1}^{\infty} \frac{\chi(n)}{n^s} (Re(s) \geq 1)
 \end{align}
@@ -158,6 +161,6 @@ Sind ferner $u \und v$ zwei Lösungen von $ax \equiv b\mod m$ , so gilt
  &\Rightarrow \frac m d | u-v \Rightarrow u\equiv v \mod \frac md
 \end{align}
 
-Alle $\mod m$ in kongruenten Lösungen sind daher gege. durch $u, u+ \frac m d, u + \frac{2m}d,\dots, u+(d-1)\frac m d$ \hfill $blacksquare$
+Alle $\mod m$ in kongruenten Lösungen sind daher gegeben durch $u, u+ \frac m d, u + \frac{2m}d,\dots, u+(d-1)\frac m d$ \hfill $\blacksquare$
 
 \end{document}
diff --git a/ue2.pdf b/ue2.pdf
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diff --git a/ue2.tex b/ue2.tex
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--- /dev/null
+++ b/ue2.tex
@@ -0,0 +1,26 @@
+\documentclass[a4paper,10pt,fleqn]{article}
+\usepackage[utf8x]{inputenc}
+\usepackage{amsmath,amssymb,ulsy}
+\usepackage{fullpage}
+
+
+\def\P{\mathbb{P}}
+\def\N{\mathbb{N}}
+\def\R{\mathbb{R}}
+\def\Z{\mathbb{Z}}
+\def\oder{\vee}
+\def\und{\wedge}
+
+\def\kgV{\text{kgV}}
+\def\ggT{\text{ggT}}
+\def\sgn{\text{sgn}}
+%opening
+\title{}
+\author{Peter Schaefer}
+
+\begin{document}
+\maketitle
+\section*{2.Übung}
+\subsection*{7. Aufgabe}
+
+\end{document}